Powershell打开文件对话框
- 作者: 名扬花满楼
- 来源: 51数据库
- 2022-09-21
Function Get-FileName($initialDirectory)
{
[System.Reflection.Assembly]::LoadWithPartialName("System.Windows.Forms") |
Out-Null
$OpenFileDialog = New-Object System.Windows.Forms.OpenFileDialog
$OpenFileDialog.initialDirectory = $initialDirectory
$OpenFileDialog.filter = "All files (*.*)| *.*"
$OpenFileDialog.ShowDialog() | Out-Null
$OpenFileDialog.filename
}
Get-FileName -initialDirectory "c:\fso"
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