for?Cletter?Cword 求解几道c程序编程题

1、

int Copy(const char* source,const char* dest){

FILE *fSource,*fDest;

fSource=fopen(source,"r");

fDest=fopen(dest,"w");

if(fSource==NULL||fDest==NULL)

return 0;

char ch;

while(feof(fSource)==0){

fread(&ch,sizeof(char),1,fSource);

if(ch>=0x61&&ch<=0x7a)

ch-=0x20;

fwrite(&ch,sizeof(char),1,fDest);

}

fclose(fSource);

fclose(fDest);

return 1;

}

2、

int Count(const char* source,int* cWord,int* cDigit,int* cLetter,int* cAll){

(*cAll)=(*cWord)=(*cDigit)=(*cLetter)=0;

FILE *fSource;

fSource=fopen(source,"r");

if(fSource==NULL)

return 0;

char bch=0,ch=0;

while(feof(fSource)==0){

fread(&ch,sizeof(char),1,fSource);

(*cAll)++;

if(isalpha(ch))

(*cLetter)++;

else if(isdigit(ch))

(*cDigit)++;

else if(isspace(ch)||ispunct(ch)||iscntrl(ch)){

if(isalpha(bch))

(*cWord)++;

}

bch=ch;

}

fclose(fSource);

return 1;

}

3、

#include<stdio.h>

#include<stdlib.h>

int j,n,sumreal,sumimaginary;

typedef struct plurality

{

int real;

int imaginary;

struct plurality * next;

}pluralityNode;

void inputplurality(pluralityNode * plurality)

{

printf("please input the real part");scanf("%d",&plurality-> real);getchar();

printf("please input the imaginary part");scanf("%d",&plurality-> imaginary);

}

pluralityNode * creatList(int n)

{

pluralityNode * p, * plurality;

int i;

plurality=(pluralityNode *)malloc(sizeof(pluralityNode));

plurality->next=NULL;

for(i=n;i>0;--i)

{

p=(pluralityNode *) malloc(sizeof(pluralityNode));

inputplurality(p);

p->next=plurality->next;plurality->next=p;

}

return(plurality);

}

void printList(pluralityNode * plurality)

{

pluralityNode * current;

current=plurality;

while(current->next!=NULL)

{

for(j=0;j<n;j++)

sumreal=sumreal+current->real;

sumimaginary=sumimaginary+current->imaginary;

current=current->next;

}

printf("The sum is:%d+%di",sumreal,sumimaginary);

}

c语言中的word和byte是什么数据类型啊

word即“字”，一个字一般是16位二进制数；

byte即“字节”，一个字节是8位二进制数。

C语言中没有word、byte类型，char、short两种类型一般是8位，相当于byte型，int一般是16位，相当于word型吧。

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