Python 输出斐波纳挈数列

    #coding:utf8    
        
    import time  
    import os  
        
    global_list = []    
      
    def test1(n):  
        if n==1 or n==2:    
            return 1    
        else:    
            return test1(n-1) + test1(n-2)    
             
    def test2(n):    
        global global_list    
        if n==1 or n==2:    
            return 1    
        else:    
            temp = test2(n-1) + test2(n-2)    
            if isinstance(temp,int):    
                global_list.append(temp)    
            return temp    
        
    def main():    
        global global_list    
        input_int = raw_input("Entry your number:")  
        length = int(input_int)  
        #第一种方法  
        start = time.clock()  
        for i in xrange(length):  
            print test1(i+1  
                        ),  
        end = time.clock()  
        print os.linesep + "处理耗时：%f s"%(end-start)  
        #第二种方法  
        start = time.clock()    
        test2(length)    
        temp_set = set(global_list)    
        global_list = [i for i in temp_set]    
        global_list.sort(reverse=True)    
        global_list.extend([1,1])    
        for i in global_list[::-1]:    
            print i,  
        end = time.clock()  
        print os.linesep + "处理耗时：%f s"%(end-start)  
        
    if __name__ == "__main__":    
        main()