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如何对 N 个列表的元素求和?

  • 作者: 周心痴727
  • 来源: 51数据库
  • 2022-10-21

问题描述

谁能给我一个提示如何聚合(总结)多个列表的特定元素?

can anybody please give me a hint how to aggregate (sum up) specific elements of multiple lists?

例如，我有 20 个名称模式相似的列表，每个列表代表相应家庭(代理)随时间推移的消费支出(即索引):

For example I have 20 lists with a similar name pattern, each representing consumption spending over time (i.e. index) of the corresponding household (agent):

c_agent_0 = [10.0, 11.0, ...]
.
.
.
c_agent_19 = [8.0, 9.0, ...]

我需要类似 value = sum of index what's in c_agent_*[whatever]

I need something like value = sum of index whatever's in c_agent_*[whatever]

推荐答案

使用 zip 将列表组合"成一个，然后对每个索引的元素求和:

Use zip to "combine" lists into single one, then sum elements for each index:

c_agent_0 = [10.0, 11.0, 12.0, 13.0, 14.0]
c_agent_1 = [1.1, 12.3, 14.2, 13.2, 14.3]
c_agent_2 = [1.4, 12.1, 14.5, 13.1, 14.2]

zipped_list = zip(c_agent_0, c_agent_1, c_agent_2)

print zipped_list
print [sum(item) for item in zipped_list]

打印

[(10.0, 1.1, 1.4), (11.0, 12.3, 12.1), (12.0, 14.2, 14.5), (13.0, 13.2, 13.1), (14.0, 14.3, 14.2)]

[12.5, 35.4, 40.7, 39.3, 42.5]
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