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计算列表中字符串的连续重复

  • 作者: 嗫?暁雲?
  • 来源: 51数据库
  • 2022-10-27

问题描述

我有一个 Python 字符串列表，

I have a Python list of strings such that,

输入:

li = ['aaa','bbb','aaa','abb','abb','bbb','bbb','bbb','aaa','aaa']

如何生成另一个列表来计算列表中任何字符串的连续重复次数?对于上面的列表，返回列表类似于:

What can I do to generate another list counting the number of consecutive repetitions of any string in the list? For the list above the return list resembles:

预期输出:

li_count = [['aaa',1],['bbb',1]['abb',2],['bbb',3],['aaa',2]]

推荐答案

使用 itertools.groupby:

from itertools import groupby
li = ['aaa','bbb','aaa','abb','abb','bbb','bbb','bbb','aaa','aaa']

a = [[i, sum(1 for i in group)] for i, group in groupby(li)]
print(a)
[['aaa', 1], ['bbb', 1], ['aaa', 1], ['abb', 2], ['bbb', 3], ['aaa', 2]]

感谢@user3483203 的改进:

Thank you @user3483203 for improvement:

a = [[i, len([*group])] for i, group in groupby(li)]
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