pandas .p??lot() x 轴刻度频率——如何显示更多刻度?
- 作者: LOVE语诺
- 来源: 51数据库
- 2022-11-15
问题描述
我正在使用 pandas .p??lot() 绘制时间序列,并希望看到每个月都显示为 x-tick.
这是数据集结构
这是 .plot() 的结果
我试图使用其他帖子和 matplotlib
- 未格式化的 x 轴
I am plotting time series using pandas .plot() and want to see every month shown as an x-tick.
Here is the dataset structure
Here is the result of the .plot()
I was trying to use examples from other posts and matplotlib documentation and do something like
ax.xaxis.set_major_locator( dates.MonthLocator(revenue_pivot.index, bymonthday=1,interval=1))
But that removed all the ticks :(
I also tried to pass xticks = df.index, but it has not changed anything.
What would be the rigth way to show more ticks on x-axis?
解决方案
No need to pass any args to MonthLocator. Make sure to use x_compat in the df.plot() call per @Rotkiv's answer.
import pandas as pd
import numpy as np
import matplotlib.pylab as plt
import matplotlib.dates as mdates
df = pd.DataFrame(np.random.rand(100,2), index=pd.date_range('1-1-2018', periods=100))
ax = df.plot(x_compat=True)
ax.xaxis.set_major_locator(mdates.MonthLocator())
plt.show()
- formatted x-axis with set_major_locator
- unformatted x-axis
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