Python:os.path.isfile 无法识别以数字开头的文件
- 作者: Destiny10309489
- 来源: 51数据库
- 2022-12-05
问题描述
所以，我正在尝试将 os.path.isfile 或 os.path.exists 合并到我的代码中，并成功找到某些常规文件(pdf，png) 搜索以字母开头的文件名时.
So, I'm trying to incorporate os.path.isfile or os.path.exists into my code with success in finding certain regular files(pdf,png) when searching for filenames that begin with a letter.
我正在使用的文件命名标准(并且由于用户而无法更改)以数字开头，随后无法使用相同的方法找到.有没有办法让 .isfile 或 .exists 发现这些文件?
The file naming standard that I'm using (and can't change due to the user) starts with a number and subsequently can't be found using the same method. Is there a way that I can make these files discoverable by .isfile or .exists?
我要搜索的文件是 .txt 文件.
The files I'm searching for are .txt files.
os.path.isfile("D:Usersspx9gsProject WorkData21022013AA.txt")
os.path.isfile("D:Usersspx9gsProject WorkDataAA21022013.txt")
返回:
错误
是的
推荐答案
你需要使用原始字符串，或者转义你的反斜杠.在文件名中:
You need to use raw strings, or escape your backslashes. In the filename:
"D:Usersspx9gsProject WorkData21022013AA.txt"
210 将被解释为八进制转义码，因此您将无法获得正确的文件名.
the 210 will be interpreted as an octal escape code so you won't get the correct filename.
以下任何一种都可以:
r"D:Usersspx9gsProject WorkData21022013AA.txt" "D:\Users\spx9gs\Project Work\Data\21022013AA.txt"
