如何在 SQL 中列出两个日期参数之间的所有日期
- 作者: 柠檬少年小豆豆
- 来源: 51数据库
- 2023-02-07
问题描述
如何在不创建存储过程、日历表或递归函数的情况下,在 SQL Server 中列出两个日期参数之间的所有日期?
How can I list all dates between two date parameters in SQL Server, without creating a stored procedure, calendar table or recursive function?
推荐答案
这使用 Master 数据库中 spt_values 表上的 Row_Number 来创建日期范围内的年、月和日期列表.然后将其内置到日期时间字段中,并进行过滤以仅返回输入的日期参数内的日期.
This uses Row_Number on the spt_values table in Master database to create a list of years, months and dates within the date range. This is then built into a datetime field, and filtered to only return dates within the date parameters entered.
执行速度非常快,并在不到 1 秒的时间内返回 500 年的日期(182987 天).
Very quick to execute and returns 500 years worth of dates (182987 days) in less than 1 second.
Declare @DateFrom datetime = '2000-01-01' declare @DateTo datetime = '2500-12-31' Select * From (Select CAST(CAST(years.Year AS varchar) + '-' + CAST(Months.Month AS varchar) + '-' + CAST(Days.Day AS varchar) AS DATETIME) as Date From (select row_number() over(order by number) as Year from master.dbo.spt_values) as Years join (select row_number() over(order by number) as Month from master.dbo.spt_values) as Months on 1 = 1 join (select row_number() over(order by number) as Day from master.dbo.spt_values) as Days on 1 = 1 Where Years.Year between datepart(year,@DateFrom) and datepart(year,@DateTo) and Months.Month between 1 and 12 and Days.Day between 1 and datepart(day,dateadd(day,-1,dateadd(month,1,(CAST(CAST(Years.Year AS varchar)+'-' + CAST(Months.Month AS varchar) + '-01' AS DATETIME))))) ) as Dates Where Dates.Date between @DateFrom and @DateTo order by 1
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