获取数字位数的最快方法?

我确实检测到了数字上的位数.例如，329586 有 6 个数字.

I have do detect the amount of digits on a number. For example, 329586 has 6 digits.

我所做的只是将数字解析为字符串，并获取字符串长度，例如:

What I done, is simply parsing the number to string, and getting the string length, like:

number.toString().length()

但是，有没有最快的方法来计算数字的位数?我必须多次使用这种方法，所以我认为使用 toString() 会影响性能.

But, is there a fastest way to count digits on a number? I have to use this method several times, so I think using toString() can impact performance.

谢谢.

Math.floor(Math.log10(number) + 1)
// or just (int) Math.log10(number) + 1

例如:

int number = 123456;
int length = (int) Math.log10(number) + 1;
System.out.println(length);

输出:

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