用户登录
用户注册

分享至

为什么我使用 =(单个等号)进行的等式比较在 Java 中不能正常工作?

  • 作者: 鵞奀昆勥
  • 来源: 51数据库
  • 2022-12-05

问题描述

我在以下行中有语法错误.但是我不明白这个错误的原因是什么.

I have a syntax error in the following line. However I can't understand what is the reason of this error.

if (address1.compareTo(address2) = 1)
        System.out.println(address1 + " is greater than " + address2);

我想要实现的是当且仅当 compareTo 返回 1 时打印正确的消息.

What I want to achieve is printing proper message if and only if compareTo returns 1.

推荐答案

你应该比较 (==) 而不是赋值 (=).这可能非常危险!为了避免这种情况,你可以使用 Yoda notation 所以而不是比较

You should compare (==) instead of assigning (=). It can be very dangerous! To avoid such situations you can use Yoda notation so instead of comparing

address1.compareTo(address2) == 1

你可以比较一下:

1 == address1.compareTo(address2)

如果缺少=,则会出现比较错误.

In case of missing =, there will be comparation error.

在你的情况下,比较一下会更好:

In your case, it would be better to compare:

address1.compareTo(address2) > 0

软件
前端设计
程序设计
Java相关