c#读取xml文件到datagridview实例

namespace queryxmlbylinq
{
    public partial class frm_main : form
    {
        public frm_main()
        {
            initializecomponent();
        }

        static string strpath = "employee.xml";
        static string strid = "";

        //窗体加载时加载xml文件
        private void form1_load(object sender, eventargs e)
        {
            getxmlinfo();
        }

        //显示选中xml节点的详细信息
        private void datagridview1_cellclick(object sender, datagridviewcelleventargs e)
        {
            strid = datagridview1.rows[e.rowindex].cells[3].value.tostring();//记录选择的职工编号
            xelement xe = xelement.load(strpath);//加载xml文件
            //使用lint从xml文件中查询信息
            ienumerable<xelement> elements = from pinfo in xe.elements("people")
                                             where pinfo.attribute("id").value == strid
                                             select pinfo;
            foreach (xelement element in elements)//遍历查询结果
            {
                textbox11.text = element.element("name").value;//显示职工姓名
                combobox1.selecteditem = element.element("sex").value;//显示职工性别
                textbox12.text = element.element("salary").value;//显示职工薪水
            }
        }

        #region 将xml文件内容绑定到datagridview控件
        /// <summary>
        /// 将xml文件内容绑定到datagridview控件
        /// </summary>
        private void getxmlinfo()
        {
            dataset myds = new dataset();
            myds.readxml(strpath);
            datagridview1.datasource = myds.tables[0];
        }
        #endregion
    }
}