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如何获取特定用户的所有 AD 组?

  • 作者: 散人zz
  • 来源: 51数据库
  • 2022-10-21

问题描述

我检查了这个已经发帖了.但它没有回答我的问题.我想获取特定用户所属的所有 Active Directory 组.

I checked this post already. But it doesn't answer my question. I want to get all the active directory groups in which a particular user is a member.

我编写了以下代码.但我无法继续,因为我不知道如何提供过滤器以及如何访问属性.

I've written the following code. But I'm not able to proceed further as I don't know how to give the filter and how to access the properties.

class Program
{
    static void Main(string[] args)
    {
        DirectoryEntry de = new DirectoryEntry("LDAP://mydomain.com");
        DirectorySearcher searcher = new DirectorySearcher(de);
        searcher.Filter = "(&(ObjectClass=group))";
        searcher.PropertiesToLoad.Add("distinguishedName");
        searcher.PropertiesToLoad.Add("sAMAccountName");
        searcher.PropertiesToLoad.Add("name");
        searcher.PropertiesToLoad.Add("objectSid");
        SearchResultCollection results = searcher.FindAll();
        int i = 1;
        foreach (SearchResult res in results)
        {
            Console.WriteLine("Result" + Convert.ToString(i++));
            DisplayProperties("distinguishedName", res);
            DisplayProperties("sAMAccouontName", res);
            DisplayProperties("name", res);
            DisplayProperties("objectSid", res);
            Console.WriteLine();
        }

        Console.ReadKey();
    }

    private static void DisplayProperties(string property, SearchResult res)
    {
        Console.WriteLine("	" + property);
        ResultPropertyValueCollection col = res.Properties[property];
        foreach (object o in col)
        {
            Console.WriteLine("		" + o.ToString());
        }
    }
}

有什么想法吗?

推荐答案

只需查询memberOf"属性并迭代返回,例如:

Just query the "memberOf" property and iterate though the return, example:

            search.PropertiesToLoad.Add("memberOf");
            StringBuilder groupNames = new StringBuilder(); //stuff them in | delimited

                SearchResult result = search.FindOne();
                int propertyCount = result.Properties["memberOf"].Count;
                String dn;
                int equalsIndex, commaIndex;

                for (int propertyCounter = 0; propertyCounter < propertyCount;
                    propertyCounter++)
                {
                    dn = (String)result.Properties["memberOf"][propertyCounter];

                    equalsIndex = dn.IndexOf("=", 1);
                    commaIndex = dn.IndexOf(",", 1);
                    if (-1 == equalsIndex)
                    {
                        return null;
                    }
                    groupNames.Append(dn.Substring((equalsIndex + 1),
                                (commaIndex - equalsIndex) - 1));
                    groupNames.Append("|");
                }

            return groupNames.ToString();

这只是将组名填充到 groupNames 字符串中,以管道分隔,但是当你旋转时,你可以对它们做任何你想做的事情

This just stuffs the group names into the groupNames string, pipe delimited, but when you spin through you can do whatever you want with them

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