PHP解析 JSON 数据
- 作者: 戒88
- 来源: 51数据库
- 2022-08-25
$json_string='{"id":1,"name":"rolf","country":"russia","office":["google","oracle"]} ';
$obj=json_decode($json_string);
//print the parsed data
echo $obj->name; //displays rolf
echo $obj->office[0]; //displays google
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