使用python获取xml节点的所有父节点

问题描述

对于这个xml

<Departments orgID="123" name="xmllist">
    <Department>
        <orgID>124</orgID>
        <name>A</name>
        <type>type a</type>
        <status>Active</status>
            <Department>
                <orgID>125</orgID>
                <name>B</name>
                <type>type b</type>
                <status>Active</status>
                <Department>
                    <orgID>126</orgID>
                    <name>C</name>
                    <type>type c</type>
                    <status>Active</status>
                </Department>
            </Department>
    </Department>
    <Department>
        <orgID>109449</orgID>
        <name>D</name>
        <type>type d</type>
        <status>Active</status>
    </Department>
</Departments>

如何在 python 中使用 lxml etree 获取节点的所有父节点.

How i can get all parents of a node using lxml etree in python.

预期输出:输入 orgid=126 ，它将返回所有喜欢的父母，

Expected output : Input orgid=126 , it will return all the parents like ,

{'A':124,'B':125,'C':126}

推荐答案

使用 lxml 和 XPath:

Using lxml and XPath:

>>> s = '''
... <Departments orgID="123" name="xmllist">
...     <Department>
...         <orgID>124</orgID>
...         <name>A</name>
...         <type>type a</type>
...         <status>Active</status>
...             <Department>
...                 <orgID>125</orgID>
...                 <name>B</name>
...                 <type>type b</type>
...                 <status>Active</status>
...                 <Department>
...                     <orgID>126</orgID>
...                     <name>C</name>
...                     <type>type c</type>
...                     <status>Active</status>
...                 </Department>
...             </Department>
...     </Department>
...     <Department>
...         <orgID>109449</orgID>
...         <name>D</name>
...         <type>type d</type>
...         <status>Active</status>
...     </Department>
... </Departments>
... '''

<小时>

使用ancestor-or-self轴，可以找到节点本身、父节点、祖父节点、...

Using ancestor-or-self axis, you can find the node itself, parent, grandparent, ...

>>> import lxml.etree as ET
>>> root = ET.fromstring(s)
>>> for target in root.xpath('.//Department/orgID[text()="126"]'):
...     d = {
...         dept.find('name').text: int(dept.find('orgID').text)
...         for dept in target.xpath('ancestor-or-self::Department')
...     }
...     print(d)
...
{'A': 124, 'C': 126, 'B': 125}