如何通过选择器方法传递 int 值?

问题描述

我想从我的选择器方法中传递一个 int 值，但是选择器方法只接受一个对象类型参数.

I want to pass an int value from my selector method, but the selector method takes only an object type parameter.

int y =0;
[self performselector:@selector(tabledata:) withObject:y afterDelay:0.1];

方法执行到这里

-(int)tabledata:(int)cellnumber {
   NSLog(@"cellnumber: %@",cellnumber);
   idLabel.text = [NSString stringWithFormat:@"Order Id: %@",[[records objectAtIndex:cellnumber] objectAtIndex:0]];
}

但我在我的方法中没有得到精确的整数值，我只得到了 id 值.

but I am not getting exact integer value in my method, I am only getting the id value.

推荐答案

如果您拥有"目标选择器，最简单的解决方案是将 int 参数包装在 NSNumber 中:

The easiest solution, if you 'own' the target selector, is to wrap the int argument in an NSNumber:

-(int)tabledata:(NSNumber *)_cellnumber {
    int cellnumber = [_cellnumber intValue];
    ....
}

要调用此方法，您将使用:

To call this method you would use:

[self performselector:@selector(tabledata:) withObject:[NSNumber numberWithInt:y] afterDelay:0.1];