AJAX/Jquery XML 解析

问题描述

我尝试解析以下类型的 XML(数据来自 getMembers.php):

I try parsing the following type of XML (data from getMembers.php):

<?xml version="1.0" encoding="ISO-8859-1"?>
<members>
   <id>3422345</id>
   <name>Bill Gates</name>
   <id>232311</id>
   <name>Bob Barker</name>
</members>

我使用下面的代码来解析它:

And I use the code below to parse it:

<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
    <script type="text/javascript">
    $(document).ready(function () {
        $.ajax({
            type: "GET",
            url: "getMembers.php",
            cache: false,
            dataType: "xml",
            success: function(xml) {
                $(xml).find('members').each(function(){
                    var name = $(this).find("name").text()
                    alert(name);
                });
            }
        });
    });
</script>

没有错误，但我同时得到了两个名字.

No error but I get both names at the same time.

喜欢:

比尔·盖茨鲍勃·巴克<--第一次循环>

Bill GatesBob Barker <--first loop>

代替

比尔盖茨<--第一个循环>

Bill Gates <--first loop>

Bob Barker <--第二个循环>

Bob Barker <--second loop>

任何帮助都会很棒！

推荐答案

我认为你迭代的是成员，而不是名字:

I think you iterate over members, not names:

success: function(xml) {
                $(xml).find('members').each(function(){
                    $(this).find("name").each(function(){
                        var name = $(this).text();
                        alert(name);
                    });
                });
            }

或者您的 XML 应该如下所示:

Or maybe your XML should looks like:

<members>
   <id>3422345</id>
   <name>Bill Gates</name>
</members>
<members>
   <id>232311</id>
   <name>Bob Barker</name>
</members>