“timestampadd"不是可识别的内置函数名称

问题描述

我正在尝试将 6 位日期转换为常规日期.

I'm trying to convert a 6 digit date into a regular looking date.

目前我们在数据库中有这个:

Currently we have this in the DB:

734562
734776
734837

这是我正在尝试的:

select 



                    timestampadd(
                                    sql_tsi_day
                                    ,rbaging.billing_period_end
                                    ,cast('0001-01-01' as sql_timestamp)
                                )
                    -1,*


 from 

[kslap208].[c021]..RB_Resident_Aging  rbaging

我得到的错误是:

Msg 195, Level 15, State 10, Line 5
'timestampadd' is not a recognized built-in function name.

如何将此字段转换为常规日期字段?

how do i convert this field into a regular date field?

推荐答案

如果远程源是一个整数，或者可以强制转换为一个，我相信应该这样做:

If the remote source is an integer, or can be cast to one, I believe this should do it:

 SELECT DATEADD(DD, Field - 730000, '2001-01-01')