利用AJAX实现鼠标悬浮获取值的代码

作者: 飞扬的青葱
来源: 51数据库
2021-08-21

客户端代码mouseover.php

复制代码代码如下:

 
<!doctype html public "-//w3c//dtd xhtml 1.0 transitional//en" "http://www.w3.org/tr/xhtml1/dtd/xhtml1-transitional.dtd"> 
<html xmlns="http://www.51sjk.com/Upload/Articles/1/0/270/270310_20210708032629630.jpg"> 
<head> 
<meta http-equiv="content-type" content="text/html; charset=utf-8" /> 
<title>鼠标悬浮测试</title> 
</head> 
<script type="text/javascript" language="javascript"> 
var xmlhttp; 
function createxmlhttprequest(){ 
if(window.activexobject){ 
xmlhttp = new activexobject("microsoft.xmlhttp"); 
} 
else if(window.xmlhttprequest){ 
xmlhttp = new xmlhttprequest(); 
} 
} 
function sendrequest(t){ 
var id = t.id 
createxmlhttprequest(); 
var url = "mouseover_check.php?page=" +t.id ; 
xmlhttp.onreadystatechange = callback; 
xmlhttp.open('get',url,true); 
xmlhttp.send(null); 
} 
function callback(){ 
if(xmlhttp.readystate == 4){ 
if(xmlhttp.status == 200){ 
document.getelementbyid("show").innerhtml = xmlhttp.responsetext; 
} 
} 
} 

</script> 
<body> 
<p> 
<input type="text" value="here" id="1" onmouseover="sendrequest(this)" /> 
</p> 
<p><br/> 
<input type="text" value="haha" id="2" onmouseover="sendrequest(this)" /> 
</div> 
</p> 
<p></p> 
<span id="show"></span> 
</body> 
</html> 

服务器端代码：
mouseover_check.php

复制代码代码如下:

 
<?php 
header("content-type:text/html;charset=utf-8"); 
header("cache-control:no-cache,must-revalidate"); 
$name = $_get['page']; 
if($name == '1'){ 
echo "111"; 
} 
else{ 
echo "222"; 
} 
?> 